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Two methods for retrieving the ListItem object that the mouse is over in a ListView control.

This code gives you two methods (one using built-in functions of the ListView control, and one using SendMessage and the LVM_GETITEMRECT constant) to retrieve the ListItem object that the mouse pointer is currently over with. This is demonstrated by highlighting the item.

Original Author: Jon B. Mooty


To test the SendMessage method set the constant USE_SENDMESSAGE to True.


The current ListItem object the mouse pointer is over.

API Declarations

Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long
Private Const LVM_GETITEMRECT = &H100E
Private Type RECT
Left As Long
Top As Long
Right As Long
Bottom As Long
End Type


' change this to true in order
' to test the SendMessage method
' you will need a ListView control
' named lvw in order to test the
' following code
Private Sub Form_Load()
  Dim iCol As Integer, iRow As Integer
  Dim sPos As String
  ' setup listview
  ' use report view with 3 columns and 500
  '   rows
  lvw.View = lvwReport
  lvw.MultiSelect = False
  lvw.ColumnHeaders.Add , , "Column1"
  lvw.ColumnHeaders.Add , , "Column2"
  lvw.ColumnHeaders.Add , , "Column3"

  For iRow = 1 To 500

    For iCol = 1 To 3
      sPos = "Row = " & iRow & ", " & "Col = " & iCol

      If iCol = 1 Then
        lvw.ListItems.Add , , sPos
        lvw.ListItems(iRow).SubItems(iCol - 1) = sPos
      End If
    Next iCol
  Next iRow
End Sub

Public Function GetListViewItemFromPt(plvw As ListView, x As Single, y As Single) As ListItem
  Dim bFound As Boolean
  Dim rCur As RECT
  Dim iIndex As Integer
  Dim iPixX As Integer, iPixY As Integer
  ' convert the coordinates to
  ' pixels (remove the next two
  ' lines if you will be passing
  ' the coordinates in pixels)
  iPixX = Me.ScaleX(x, vbTwips, vbPixels)
  iPixY = Me.ScaleY(y, vbTwips, vbPixels)

  For iIndex = 1 To plvw.ListItems.Count
    ' get the coordinates for each
    ' item in the listbox in its current
    ' state, if Top is less than 0 or Bottom
    ' is greater than the height of the
    ' listbox then the item is currently out
    '   of the
    ' viewable area
    rCur.Left = 0
    SendMessage plvw.hwnd, LVM_GETITEMRECT, iIndex, rCur
    ' if passed corrdinates are within
    ' the bounds of the current item than
    ' exit the loop and return the ListItem
    '   object

    If iPixY >= rCur.Top And iPixY <= rCur.Bottom Then
      bFound = True
      Exit For
    End If
  Next iIndex

  If bFound Then
    Set GetListViewItemFromPt = plvw.ListItems(iIndex + 1)
    Set GetListViewItemFromPt = Nothing
  End If
End Function

Private Sub lvw_MouseMove(Button As Integer, Shift As Integer, x As Single, y As Single)
  ' set the selected ListItem object equal
  '   to the Item the mouse
  ' is currently over
    Set lvw.SelectedItem = GetListViewItemFromPt(lvw, x, y)
    Set lvw.SelectedItem = lvw.HitTest(x, y)
  #End If
End Sub

About this post

Posted: 2002-06-01
By: ArchiveBot
Viewed: 126 times


Visual Basic 6


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